I have a nested list like this:
list1 = [1,2,3]
list2 = [4,5,6]
list_all = [list1,list2]
My question is in a for loop how to get the list1 and list2 as a name of the list:
for i in list_all:
print(list1.name,list2.name)
Output should like:
"list1",'list2'
If you make the lists dictionaries you can provide a name
list1 = { "name": list1, "list": [1,2,3]}
list2 = { "name": list2, "list": [4,5,6]}
list_all = [list1,list2]
for i in list_all:
print(list_all[i].name)
It's a bit complicated and inefficient but it works:
list1 = [1,2,3]
list2 = [4,5,6]
list_all = [list1,list2]
i = k = v = None
# we need this line to avoid "RuntimeError: dictionary changed size during iteration" so locals() will recognize them
loc = locals().items()
for i in list_all:
for k,v in loc:
if v is i and k != 'i':
# if id(v) equal to id(i)
print(k)
and the output will be:
list1
list2
list_allis exactly equivalent to[[1,2,3],[4,5,6]]- there is absolutely no way to tell that the sub-lists came from individual variables, rather than being written directly in the assignment.