How to pass parameters in a POST() request using the new HTTP client in Java

Question

I just started using the new HTTP client in Java and I'm unsure on how to pass parameters for a PUT request.

The specific request I'm dealing with requires an Authentication token and a parameter type.

I've successfully dealt with the Authentication token using .headers()
I tried to do the same thing with the type parameter but I get an error message that states I haven't passed a type field.

HttpClient client = HttpClient.newBuilder().build();
HttpRequest request = HttpRequest.newBuilder()
                .uri(URI.create("...")) # The API url
                .headers("Authorization", token, "type", "type 1")
                .POST(HttpRequest.BodyPublishers.noBody())
                .build();

HttpResponse<String> response = client.send(request,HttpResponse.BodyHandlers.ofString());
System.out.println(response.body());

Is the type parameter expected to be a header? isn't it a query parameter... URI.create("...?type=type1")? — ernest_k
– ernest_k, Commented May 11, 2021 at 8:24
Thank you so much... If I had multiple parameters, how would I do it? would it be like URI.create("...?param1 = ... ? param2 = ...) — Mistakamikaze
– Mistakamikaze, Commented May 11, 2021 at 9:00
Thank you so much... Is there a way I can turn your comments into an answer? — Mistakamikaze
– Mistakamikaze, Commented May 11, 2021 at 9:06
Your question needs to be made clearer first and then you can answer it. — ernest_k
– ernest_k, Commented May 11, 2021 at 9:09

Mistakamikaze · Accepted Answer · 2021-05-11 10:23:25Z

1

As @ernest_k commented, we can pass parameters through by appending them to the end of the URL in this format: ?type=type1&param2=value2&param3=value3&param4=value4

HttpClient client = HttpClient.newBuilder().build();
HttpRequest request = HttpRequest.newBuilder()
                .uri(URI.create("..." + "?type=type 1"))
                .headers("Authorization", token)
                .POST(HttpRequest.BodyPublishers.noBody())
                .build();

HttpResponse<String> response = client.send(request,HttpResponse.BodyHandlers.ofString());
System.out.println(response.body());

answered May 11, 2021 at 10:23

Mistakamikaze

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