Removing specific value from list of key value pair from Dictionary in Python

Question

Below is the dictionary set I have

dict = {'city':[('hyderabad','pune','chennai'),'state':[('Telangana','mumbai','tamilnadu')]}

I'm trying to remove the first two strings from the list in key value pair from this dictionary, so it will look the same as below

dict = {'city':[('chennai'),'state':[('tamilnadu')]}

I have tried:

for v in dict.values():
    del v[0:1]

but this deletes the whole list instead of first two indexes, need help in deleting only the first two indexes of each value list in key value pair

Please refrain from using pandas for trivial data structure manipulations like these. — Vishnudev Krishnadas
– Vishnudev Krishnadas, Commented Jun 22, 2021 at 18:21

Andrej Kesely · Accepted Answer · 2021-06-22 18:06:53Z

3

You can use list slicing:

dct = {
    "city": [("hyderabad", "pune", "chennai")],
    "state": [("Telangana", "mumbai", "tamilnadu")],
}

dct = {k: [l[2:] for l in v] for k, v in dct.items()}
print(dct)

Prints:

{
 'city': [('chennai',)], 
 'state': [('tamilnadu',)]
}

answered Jun 22, 2021 at 18:06

Andrej Kesely

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Comments

Carmoreno · Accepted Answer · 2021-06-22 18:17:06Z

3

Try this:

dictionary = {
   'city':[('hyderabad','pune','chennai')],
   'state':[('Telangana','mumbai','tamilnadu')]
}
dict_new = {}
for key, value in dictionary.items():
  dict_new[key] = [value[0][2:],]

print(dict_new)

Or, if you prefer to use comprehension notation...

dict_new = {key: [value[0][2:],] for key, value in dictionary.items()}
print(dict_new)

Output:

{
   'city': [('chennai',)], 
   'state': [('tamilnadu',)]
}

Btw.. Try don't use reserved words like dict, tuple, str, etc. like variables names

edited Jun 22, 2021 at 18:17

answered Jun 22, 2021 at 18:11

Carmoreno

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