getting a specific XML tag element in Java

Question

I have the following XML:

<oa:Parties>
  <ow-o:SupplierParty>
    <oa:PartyId>
      <oa:Id>1</oa:Id>
    </oa:PartyId>
  </ow-o:SupplierParty>
  <ow-o:CustomerParty>
    <oa:PartyId>
      <oa:Id>123-123</oa:Id> // I NEED THIS
    </oa:PartyId>
    <oa:Business>
      <oa:Id>ShiptoID</oa:Id>
    </oa:Business>
  </ow-o:CustomerParty>
</oa:Parties>

How can I get the 123-123 value?

I tried this:

NodeList nodeList = document.getElementsByTagName("ow-o:CustomerParty");
Node parentNode = nodeList.item(0);
String ID = parentNode.getTextContent();

But it has both <oa:Id> elements.

Is there a way to find the value based on hierarchy ow-o:CustomerParty > oa:PartyId > oa:Id?

L_Cleo · Accepted Answer · 2021-06-25 16:42:20Z

1

I’d just go with A simple filter on its child items. This way

NodeList nodeList = document.getElementsByTagName("ow-o:CustomerParty");
Node parentNode = nodeList.item(0);

Node partyNode = filterNodeListByName(parentNode.getChildNodes(), "oa:PartyId");

Node idNode = null;
if(partyNode!=null)
    idNode = filterNodeListByName(partyNode.getChildNodes(), "oa:Id")

String ID = idNode!=null ? idNode.getTextContent() : "";

Basically the first filter gets all the child items matching the node name "oa:PartiId". It then maps the found node (I used findAny but findFirst could still be a viable option in your case) to the child item node's, with name oa:id, text content

SN: I’m considering you’ll define a method such so

public boolean isNodeAndWithName(Node node, String expectedName) {
    return node.getNodeType() == Node.ELEMENT_NODE && expectedName.equals(node.getNodeName());
}

And this is the additional method

public Node filterNodeListByName(NodeList nodeList, String nodeName) {
        for(int i = 0; i<nodeList.getLength(); i++)
            if(isNodeAndWithName(nodeList.item(i), nodeName)
                return nodeList.item(i);
        return null;
}

edited Jun 25, 2021 at 16:42

answered Jun 25, 2021 at 0:20

L_Cleo

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5 Comments

A.J Over a year ago

Thanks for the response. I tried this solution but looks like NodeList does not have stream(). I am getting an error error: cannot find symbol: method stream() location: interface NodeList

L_Cleo Over a year ago

My bad I'm used to a library which gave you the list I'm gonna fix it right away

L_Cleo Over a year ago

@AJ let me know, this is adapted to default NodeList object

A.J Over a year ago

Thank you, it worked! Just wanted to point out in case someone else comes across it, the method is getChildNodes(), not getChildItems(). And the isNodeWithName method name does not match, so you can edit your question if you like with those changes. Thanks again!

L_Cleo Over a year ago

Thanks my bad, copying the code I lost some parts

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