String with literal unicode value to unicode character in Rust

Question

So i have a string for example like

"HITMAN\u2122 Free Trial"

is there any way i can convert the \u2122 to an actual unicode character so that the string would look like this

"HITMAN™ Free Trial"

Edit: for clarification the first string is an utf-8 string from an api, and i need to parse it for display

You mean, how to represent "HITMAN™ Free Trial" in source code using the \u escape or convert "HITMAN\\u2122 Free Trial" at runtime? — dumbass
– dumbass, Commented Jul 11, 2021 at 15:56

Riton Elion · Accepted Answer · 2021-07-11 15:51:16Z

8

Just add {and} around 2122, like this:

let unicode_str = "HITMAN\u{2122} Free Trial";
println!("{}", unicode_str);

answered Jul 11, 2021 at 15:51

Riton Elion

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1 Comment

DrVilepis Over a year ago

Sorry i was bit unclear, I added some clarification.

Denys Séguret · Accepted Answer · 2021-07-11 16:08:33Z

The first encoding is the one you find in many languages, and for example in JSON. It differs from Rust literals in which you have \u{2122} instead of \u2122.

This gives us a solution: parse it as JSON.


let s = "HITMAN\\u2122 Free Trial";
let s: String = serde_json::from_str(&format!("\"{}\"", s)).unwrap();
assert_eq!(
    s,
    "HITMAN™ Free Trial",
);

But while this is useful as validation, you probably don't want to include a deserializer just for this, so you probably want to do the parsing yourself, for example with a regular expression:

use lazy_regex::*;

let s = "HITMAN\\u2122 Free Trial";
let s = regex_replace_all!(r#"\\u(\d{4})"#, s, |_, num: &str| {
    let num: u32 = u32::from_str_radix(num, 16).unwrap();
    let c: char = std::char::from_u32(num).unwrap();
    c.to_string()
});
assert_eq!(
    s,
    "HITMAN™ Free Trial",
);

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