Replacing output text of a command with a string in a Shell Script

Question

Hello and thank you for any help you can provide

I have my Apache2 web server set up so that when I go to a specific link, it will run and display the output of a shell script stored on my server. I need to output the results of an SVN command (svn log). If I simply put the command 'svn log -q' (-q for quiet), I get the output of:

(of course not blurred), and with exactly 72 dashes in between each line. I need to be able to take these dashes, and turn them into an html line break, like so:

<br />

Basically I need the shell script to take the output of the 'svn log -q' command, search and replace every chunk of 72 dashes with an html line break, and then echo the output.

Is this at all possible? I'm somewhat a noob at shell scripting, so please excuse any mess-ups.

Thank you so much for your help.

Do you really hate <pre> that much?

Ignacio Vazquez-Abrams
– Ignacio Vazquez-Abrams

2011-07-27 22:12:51 +00:00
Commented Jul 27, 2011 at 22:12 — Ignacio Vazquez-Abrams
– Ignacio Vazquez-Abrams, Commented Jul 27, 2011 at 22:12

s4y · Accepted Answer · 2011-07-27 23:54:14Z

2

 svn log -q | sed -e 's,-{72},<br/>,'

edited Jul 27, 2011 at 23:54

s4y

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answered Jul 27, 2011 at 22:13

Bohemian♦

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3 Comments

Michael Levvington Over a year ago

I tried putting it into my shell script exactly like this and nothing was printed on the page. Any other suggestions? Thanks for your help.+

s4y Over a year ago

There should not be quotes around svn log -q. @Bohemian, hope you don't mind if I edit to fix…

tripleee Over a year ago

There are differences in sed syntax. Instead of guess which syntax yours supports, try svn log -q | perl -pe 's,^-{72}$,<br/>,'

Shaunak · Accepted Answer · 2011-07-27 22:19:37Z

0

If you want to write it in the script this might help:

${string//substring/replacement}
Replace all matches of $substring with $replacement.

stringZ=abcABC123ABCabc

echo ${stringZ/abc/xyz}       # xyzABC123ABCabc
                              # Replaces first match of 'abc' with 'xyz'.

echo ${stringZ//abc/xyz}      # xyzABC123ABCxyz
                              # Replaces all matches of 'abc' with # 'xyz'.

answered Jul 27, 2011 at 22:19

Shaunak

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