pass variable to php form after submitting the form

Question

I want to pass the variable from php page to another without using sessions.

here's SearchCustomer.php page which have the from

<form action="controllers/Customer.controller.php" method="post">
<label for="cellPhoneNo">cell phone number</label>
    <input type="text" name="cellPhoneNo" class="textField"/>
    <span id="cellphonePrefix"></span>

    <label for="telephone">telephone </label>
    <input type="text" name="telephone" class="textField"/>

    <input type="submit" name="searchCustomer" value="بحث"/>

in Customer.controller.php I search for customer and return a $result, I want to pass the variables defined in Customer.controller.php to SearchCustomer.php page which the from is submitted from without using sessions.

JK. · Accepted Answer · 2011-08-08 13:02:14Z

5

You can achieve this with hidden input controls.

In Customer.controller.php:

echo "<input type='hidden' name='result' value='{$result}'>";

In SearchCustomer.php:

$passedResult = $_POST['result'];

Update: Question did change a bit, use a redirect similar to this:

header("Location: http://yoursite.com/SearchCustomer.php?result={$result}");

edited Aug 8, 2011 at 13:02

answered Aug 8, 2011 at 12:45

JK.

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1 Comment

palAlaa Over a year ago

In Customer.controller.php I use header to redirect to SearchCustomer.php page, so I can't use echo before it!

Quasdunk · Accepted Answer · 2011-08-09 08:20:46Z

As far as I understand your problem: You want to perform the search in Customer.controller.php and immediately display the results in SearchCustomer.php, right?

Well, that smells like AJAX :)

Try this (using jQuery):

SearchCustomer.php

<form id="search_form" action="controllers/Customer.controller.php" method="post">
//...
</form>

<div id="output">
</div>

<script>
$('#search_form').submit(function() {
  $.post($(this).attr('action'), $(this).serialize(), function(data) {
    for(var i = 0; i < data.length; i++) {
      $('#output').append('field one: ' + data[i].field1 + '<br />');
    }
  }, 'json');
  return false;
});
</script>

Customer.controller.php

<?php

$cellPhoneNo = $_POST['cellPhoneNo'];
//....

//perform the search, 
//fetch the assoc-array, e.g. $results 
echo json_encode($results);

The code is untested, but you get the idea ;)

linuxeasy · Accepted Answer · 2011-08-08 13:06:39Z

2

You could make use of hidden fields some way!

for example:

<input type="hidden" name="multiPageValue" 
value="<?php echo $_POST['multiPageValue'];?>"/>

and you can go on using this snipped on all the consecutive pages to which you would be navigating by submitting form!

edited Aug 8, 2011 at 13:06

answered Aug 8, 2011 at 12:47

linuxeasy

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1 Comment

linuxeasy Over a year ago

@Linus Kleen Well, the problem asked was not about XSS test, but a simple problem, of retaining values to multiple pages!, to test it specifically for XSS, he may choose his own way, as using htmlspecialchars() or whatever better strategy he uses! how awkward it would had been to show and example like value="<?php echo htmlspecialchars($_POST['multiPageValue']);?>"/>, thanks for your negative point, though it doesn't makes any sense to me! :)

Richard Testani · Accepted Answer · 2011-08-08 13:06:47Z

2

Once a user submits your form, your server will handle the form data sent to it. PHP takes that and parses it for you in an array named $_POST.

PHP $_POST

Since you do not define an action in your form, the _POST array will be available to the same page as your form once its submitted. Do a simple test at the top of your page:

if(isset($_POST['cellPhoneNo'])) {
 echo "Thank you for your phone numbers!";
}

answered Aug 8, 2011 at 13:06

Richard Testani

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