php json, get determined user id [duplicate]

Question

i have this json file with written

[
{"image_member_id":"17665","image_id":"11160","image_caption":"dalla bacheca"},
{"image_member_id":"17310","image_id":"11159","image_caption":"dalla bacheca"},
{"image_member_id":"17310","image_id":"11158","image_caption":"dalla bacheca"},
{"image_member_id":"17780","image_id":"11157","image_caption":"dalla bacheca"},
]

I call the file with

$jsondata = file_get_contents("uploads/file/file-text-dati-globali/foto-galleria/gallery.json");
$json_a = json_decode($jsondata);

how can i download user ids only image_member_id 17310

{"image_member_id":"17310","image_id":"11159","image_caption":"dalla bacheca"}, {"image_member_id":"17310","image_id":"11158","image_caption":"dalla bacheca"}, i am using foreach but i download all records, i just want to download id 17310

Decode it to an associative array (check the json_decode manual page for how to do that). Once you've done that, there are soooo many answers to this already (and it's absolutely nothing to do with JSON - once you've decoded the data, it's just a regular old PHP multidimensional associative array which you can search in. The fact that it used to be JSON is completely irrelevant.). — ADyson
– ADyson, Commented Nov 24, 2021 at 15:36
stackoverflow.com/questions/1019076/…, stackoverflow.com/questions/8102221/…, stackoverflow.com/questions/6661530/…, stackoverflow.com/questions/42397219/…, stackoverflow.com/questions/10152920/…, and so on. You can easily find more with some simple searches — ADyson
– ADyson, Commented Nov 24, 2021 at 15:37

mt.i.1 · Accepted Answer · 2021-11-24 15:46:54Z

0

You can use array_filter to achieve this

$json_a = json_decode($jsondata, true); //associative array
$id_search = 17310;
$results = array_filter($json_a, function($v, $k) use ($id_search) {
    return $v['image_member_id'] == $id_search;
}, ARRAY_FILTER_USE_BOTH);

answered Nov 24, 2021 at 15:46

mt.i.1

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2 Comments

natoduevolte Over a year ago

thanks! I solved it like this

mt.i.1 Over a year ago

you're welcome, please mark my answer as the accepted answer :)

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