TypeScript define object where keys will be from Type?

Question

How can I define a type for an object where the keys will come from list that I know, in this case field_1 and field_2

type FooKey = 'field_1' | 'field_2';
interface FooValue {
  src: string;
  id: number;
}
interface Foo {
  [FooKey]: FooValue;
}

const thing: Foo = {
  field_1: {
    src: 'src 1',
    id: 1,
  },
  field_2: {
    src: 'src 2',
    id: 2,
  },
};

Add every field to the type and make them optional.

Peter
– Peter

2021-11-29 14:35:47 +00:00
Commented Nov 29, 2021 at 14:35 — Peter
– Peter, Commented Nov 29, 2021 at 14:35

Drag13 · Accepted Answer · 2021-11-29 14:37:33Z

1

Simply use Record

const d: Record<FooKey, FooValue > = {...}

answered Nov 29, 2021 at 14:37

Drag13

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1 Comment

Drag13 Over a year ago

@Evanss did this answer your question?

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