How to print full char array gdb

Question

How do I print the full aligned_depth.get_data(). It should be a char array: https://gist.github.com/richardrl/224eb53d4bc1cedda36f5bda1d78ca18#file-realsense_multicam-cpp-L390

These are a few things I tried:

(gdb) print *aligned_depth.get_data()@depth_size
Attempt to dereference a generic pointer.
(gdb) print (char*) aligned_depth.get_data()@depth_size
Only values in memory can be extended with '@'.
(gdb) print (char*)aligned_depth.get_data()@depth_size
Only values in memory can be extended with '@'.

get_data is here: https://intelrealsense.github.io/librealsense/doxygen/classrs2_1_1frame.html#a4b373fc81617be881b691a97b0f8358c

Assign the result of get_data() to a variable, then print that. — Barmar
– Barmar, Commented Dec 31, 2021 at 20:19
this might help you: stackoverflow.com/questions/29528732/… — أكثم الحميدات
– أكثم الحميدات, Commented Dec 31, 2021 at 22:33

Employed Russian · Accepted Answer · 2022-01-01 06:15:30Z

1

This should work:

(gdb) p *((char*)aligned_depth.get_data())@depth_size

At least it does work for me using GDB-10.0 given this test:

const char p[] = "abcd\0efgh";
const int  data_size = sizeof(p);
const void* get_data() { return p; }

int main() { return 0; }

gcc -g -w x.c && gdb -ex start -q ./a.out

Reading symbols from ./a.out...
Temporary breakpoint 1 at 0x113a: file x.c, line 5.
Starting program: /tmp/a.out

Temporary breakpoint 1, main () at x.c:5
5       int main() { return 0; }

(gdb) p *((char*)get_data())@data_size
$1 = "abcd\000efgh"

answered Jan 1, 2022 at 6:15

Employed Russian

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1 Comment

milahu Over a year ago

does that work with dynamic size? print (char[$eax])*($rbx) is a syntax error. there seems to be no eval in gdb... currently i use p/x *($rbx)@$eax but thats verbose

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