a = input("enter your first name ")
for i in range(len(a)):
for space in range(len(a)-i):
print(end=' '*len(a))
for j in range(2*i+1):
print(a,end = '')
print()
print()
if a == 'Allahyar' or 'allahyar':
print(a+ ' is a boomer')
elif a != 'Allahyar' or 'allahyar':
print(a+' has been sent to the pyramid realm')
in this code the if statement executes no matter what and it completely ignores the elif statement. any idea why?
Correct syntax to combine two conditions using logical or operator.
if var == "str1" or var == "str2":
You can also do it like this
if var in ["str1","str2"]:
I'll expand on my comment. The reason you're getting the if condition always triggering is because you think that what you coded should equate to: "variable a is equal to either 'Allahyar' or 'allahyar'" but in reality it will get evaluated as two separate statements like so (brackets added for clarity):
(a == 'Allahyar') or (bool('allahyar'))
A non-empty string 'allahyar' will always evaluate to True so it's impossible for this combined expression to be False.
as @pavel stated the correct code is 𝐚 == '𝐀𝐥𝐥𝐚𝐡𝐲𝐚𝐫' 𝐨𝐫 𝐚 == '𝐚𝐥𝐥𝐚𝐡𝐲𝐚𝐫' I just got confused so I made an elif statement but the actual code was this a = input("enter your first name ")
for i in range(len(a)):
for space in range(len(a)-i):
print(end=' '*len(a))
for j in range(2*i+1):
print(a,end = '')
print()
print()
if a == 'Allahyar' or a == 'allahyar':
print(a+ ' is a boomer')
else:
print(a+' has been sent to the pyramid realm')
there is no reason for the elif statement its just extra code to write for no reason.
a == 'Allahyar' or a == 'allahyar'ora in ['Allahyar', 'allahyar']. Or even simplera.lower() == 'allahyar'. This is because how conditions are evaluated in your expression.