for loop with zip in python

Question

I want to use zip to iterate to existing Lists.

I did that with the code below. Currently the output is just Name --> Name.

How do I use the new creates list or if that's not possible the other lists to print following sentence:

“#NAME is #AGE years old, and they can be called at #NUMBER”. Is it possible to accomplish this in a single loop?

    birth_years = {"Alice": "1990", "Bob": "1990", "Carol": "1995", "Felix":"1995","Max":"1995","Chris":"1998","Lea":"1998","Linn":"1998","Julia":"1998"}
    book = {"Alice": "+1554", "Bob": "+1885", "Carol": "+1006", "Felix":"+1604", "Max":"+1369","Chris":"+1882","Lea":"+1518","Linn":"+1742","Julia":"+1707"} 


   def test(birth_years, books):
      new_list = []
      for birth_year, book in zip(birth_years, books):
        new_list.append(f'{birth_year} -> {book}')
      return new_list

   print(test(birth_years,books))

Thanks!!

BR

justANewb stands with Ukraine · Accepted Answer · 2022-06-04 09:10:10Z

1

zip is not the problem here. The problem is your for loop will simply loop over the keys in the dictionary, rather than the keys and values (see this answer)

The correct way of doing this is:

birth_years = {"Alice": "1990", "Bob": "1990", "Carol": "1995", "Felix":"1995","Max":"1995","Chris":"1998","Lea":"1998","Linn":"1998","Julia":"1998"}
books = {"Alice": "+1554", "Bob": "+1885", "Carol": "+1006", "Felix":"+1604", "Max":"+1369","Chris":"+1882","Lea":"+1518","Linn":"+1742","Julia":"+1707"} 


def test(birth_years, books):
    new_list = []
    for [name, birth_year], [unused, number] in zip(birth_years.items(), books.items()):
        new_list.append(f'{name} is {2022 - int(birth_year)} years old, and they can be called at {number}')
    return new_list

print(test(birth_years,books))

answered Jun 4, 2022 at 9:10

justANewb stands with Ukraine

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8 Comments

Max Over a year ago

Hey thanks for your answer. What is unused, number for?

justANewb stands with Ukraine Over a year ago

I name it unused because it is unused :). Specifically, both name and unused store the name.

Max Over a year ago

Is it also possible to something like this, that you won't get every name in the output?

justANewb stands with Ukraine Over a year ago

1) Yes, you can create a dict which key's are the names, and value are the string

justANewb stands with Ukraine Over a year ago

2) you have to create the dict :) so you could use the input

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