Python, Matplotlib; drawing a partial circle

Question

I can draw a full circle like so:

plt.figure()
ax = plt.gca()

# Make the circle patch and add to the figure
circle = plt.Circle((1, 0), 1, color='r', fill=None)
ax.add_patch(circle)
    
# Make it a perfect circle by making it a perfect square box
ax.set_aspect('equal', adjustable='box')
    
# Set axis so it's visible 
plt.xlim([-0.5,2.5])    
plt.ylim([-1.5, 1.5])

So far so good. But, what I only want a portion of the circle? For example, something that looks like this.

I could just plot something on top of it with the same color as the background, but that seems a little hacky. Is there a better way?

A partial circle is an arc. You just need to draw an arc instead of a circle — Colim
– Colim, Commented Jun 29, 2022 at 7:44

mozway · Accepted Answer · 2022-06-29 07:45:00Z

2

What about using an Arc?

from matplotlib.patches import Arc
radius = 1
arc = Arc((1, 0), radius*2, radius*2, color='b', theta1=90, theta2=360)
ax.add_patch(arc)

output:

output on top of the original circle:

answered Jun 29, 2022 at 7:45

mozway

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1 Comment

Mitchell van Zuylen Over a year ago

Ahh, that's perfect! This is actually what I want. I must have missed it in the docs.

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