How to generate dynamic json in dart

Question

Currently, I have the following JSON:

var user = {
                          "id": Provider.of<UserProvider>(context, listen: false).id,
                          "name": Provider.of<UserProvider>(context, listen: false).name,
                          "desc": Provider.of<UserProvider>(context, listen: false).desc,
                          "title": Provider.of<UserProvider>(context, listen: false).title
                        };

var finalJson = json.encode(user);

Now I want to exclude desc key and value if Provider.of(context, listen: false).desc == null.

I do not want to include key and value if anyone the value is null.

How can I achieve that?

Ivo · Accepted Answer · 2022-06-30 11:55:23Z

2

Just call

user.removeWhere((key, value) => value == null);

before you encode it

answered Jun 30, 2022 at 11:55

Ivo

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Sulaymon Ne'matov · Accepted Answer · 2022-06-30 11:48:16Z

1

Here's a simpler way to do it:

Map<String, dynamic> user = {};
if (Provider.of<UserProvider>(context, listen: false).id != null) {user["id"] = Provider.of<UserProvider>(context, listen: false).id;}
if (Provider.of<UserProvider>(context, listen: false).name != null) {user["name"] = Provider.of<UserProvider>(context, listen: false).name;}
if (Provider.of<UserProvider>(context, listen: false).desc != null) {user["desc"] = Provider.of<UserProvider>(context, listen: false).desc;}
if (Provider.of<UserProvider>(context, listen: false).title != null) {user["title"] = Provider.of<UserProvider>(context, listen: false).title;}

var finalJson = json.encode(user);

answered Jun 30, 2022 at 11:48

Sulaymon Ne'matov

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