How to convert a string to array of strings made of characters in c++?

Question

How to split a string into an array of strings for every character? Example:

INPUT:
string text = "String.";

OUTPUT:
["S" , "t" , "r" , "i" , "n" , "g" , "."]

I know that char variables exist, but in this case, I really need an array of strings because of the type of software I'm working on.

When I try to do this, the compiler returns the following error:

Severity    Code    Description Project File    Line    Suppression State
Error (active)  E0413   no suitable conversion function from "std::string" to "char" exists

This is because C++ treats stringName[index] as a char, and since the array is a string array, the two are incopatible. Here's my code:

string text = "Sample text";
string process[10000000];

for (int i = 0; i < sizeof(text); i++) {
    text[i] = process[i];
}

Is there any way to do this properly?

Shouldn't the code example use process[i] = text[i], assuming that text is your input string you want to chop up in the way you describe..? — saxbophone
– saxbophone, Commented Jul 24, 2022 at 13:45
Another code issue, you can't use sizeof() to get the length of string as number of characters, you need to call str.length() — saxbophone
– saxbophone, Commented Jul 24, 2022 at 13:46
@saxbophone I totally agree. Meant it as a side note (and updated my comment accordingly). — wohlstad
– wohlstad, Commented Jul 24, 2022 at 13:50
The sub problem that you need to solve is how to create an object of type std::string that holds a single character. When you’ve got that, repeat until done. — Pete Becker
– Pete Becker, Commented Jul 24, 2022 at 13:50
It doesn't really help to start with the problem you are not trying to solve, but anyway reopened, the duplicate was incorrect. — john
– john, Commented Jul 24, 2022 at 14:03

john · Accepted Answer · 2022-07-24 14:01:52Z

2

If you are going to make string, you should look at the string constructors. There's one that is suitable for you (#2 in the list I linked to)

for (int i = 0; i < text.size(); i++) {
    process[i] = string(1, text[i]); // create a string with 1 copy of text[i]
}

You should also realise that sizeof does not get you the size of a string! Use the size() or length() method for that.

You also need to get text and process the right way around, but I guess that was just a typo.

edited Jul 24, 2022 at 14:01

answered Jul 24, 2022 at 13:48

john

88.3k5 gold badges61 silver badges95 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Aleksandr Medvedev · Accepted Answer · 2022-07-24 14:03:53Z

2

std::string is a container in the first place, thus anything that you can do to a container, you can do to an instance of std::string. I would get use of the std::transform here:

const std::string str { "String." };
std::vector<std::string> result(str.size());
std::transform(str.cbegin(), str.cend(), result.begin(), [](auto character) {
    return std::string(1, character);
});

answered Jul 24, 2022 at 14:03

Aleksandr Medvedev

10.3k3 gold badges25 silver badges66 bronze badges

Collectives™ on Stack Overflow

How to convert a string to array of strings made of characters in c++?

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related