Get the biginteger number from String in java

Question

I'm trying to parse messages I receive using AT+CMGL command.

My main interest is to get the 15 digit number from the message and store it in a table.

Here's an example of the data the I receive :

+CMGL: 0,"REC READ","+212664090320",,"22/09/14,10:58:33+04"
876011033120958
+CMGL: 0,"REC READ","+212664486654",,"22/09/14,11:47:33+04"
Ver:03.27.07_00 GPS:AXN_5.1.9 Hw:FMB920 Mod:13 IMEI:350444465129844 Init:2022-9-6 12:0 Uptime:1193 MAC:380A2986D9CB SPC:1(0) AXL:0 OBD:0 BL:1.10 BT:4

fyi, i get 8 different message format, I've just listed two here.

You mean the IMEI? You don't need to do calculations on it, so keep it as a string, don't try to parse it as a BigInteger (if that's what you meant with your title). — Federico klez Culloca
– Federico klez Culloca, Commented Sep 14, 2022 at 11:55
Well, if you know there is only 1 15-digit number you can use a regex like ([0-9]{15}) along with classes Pattern and Matcher. — Thomas
– Thomas, Commented Sep 14, 2022 at 11:55
The IMEI is an identifier that happens to be numerical, but it doesn't make sense to do arithmetic operations on it (What would be the meaning of myIMEI + 10 for example?). So leave it as a string and use it as a string only. — QBrute
– QBrute, Commented Sep 14, 2022 at 11:58

rzwitserloot · Accepted Answer · 2022-09-14 12:58:30Z

Number storage mechanisms are for numbers, i.e. things you intend to do math on. It makes no sense to add 1 from an IMEI, or to subtract one IMEI from another. I doubt it's particularly sensible, therefore, to use BigInteger as storage format for an IMEI. String is fine.
To extract the IMEI from such input, regular expressions seem useful. I'd try \bIMEI:(\d{15,16})\b. That means: A 'word break', then IMEI:, then either 15 or 16 digits, then another word break. (IMEI are 15 or 16 digits currently). You can future proof matters by just using \\d+, which means '1 or more digits'. The parentheses also allow us to get that number out later. Then, make a matcher, find(), and ask for group(1):

private static final Pattern IMEI_FINDER = Pattern.compile("\\bIMEI:(\\d{15,16})\\b");

public String extractImei(String in) {
  Matcher m = IMEI_FINDER.matcher(in);
  if (m.find()) return m.group(1);
  throw new IllegalArgumentException("No IMEI found: " + in);
}

The above will return the first IMEI found in the input. You can repeatedly call find() if there are multiple IMEI: entries in there and you want them all; something like:

while (m.find()) imeiList.add(m.group(1));

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