How to assign a value to a variable with a dynamically created name?

Question

I know this is a no-no...and yes, I still want to do it or at least know how to do it. I would like to set the value of a variable in Perl for which the name is dynamically created (I am looping through different arrays of strings). I know I could do it rather straightforwardly with a hash array, but I'm just curious how you do this with a scalar variable, e.g.

$time  = 't0';
$color = 'blue';

I want to create the variable

$bluet0 = 1;

I've tried

${time.$color} = 1

but that doesn't work.

It would work except time is a builtin perl function. Use ${"time" . $color} or ${"time$color"}. — mob
– mob, Commented Sep 22, 2022 at 13:54
@ikegami: Really I am not understand your question. However my comment and the OP's question both are same I thought. Your opinion please? — ssr1012
– ssr1012, Commented Sep 24, 2022 at 11:33

ikegami · Accepted Answer · 2022-09-22 15:43:14Z

4

Replace

${ time . $color } = 1;

with

no strict qw( refs );

${ $color . $time } = 1;

Like you said, this is something to avoid.

edited Sep 22, 2022 at 15:43

answered Sep 22, 2022 at 13:55

ikegami

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3 Comments

gj. Over a year ago

And just to add to ikegami's solution (thank you!), which I had tried as well and the reason why it didn't work for me was that I was also initializing my variable with my, i.e. my $bluet0 = 0; before that -- the no strict line gave me the hint to remove that.

ikegami Over a year ago

Symbolic references can only reference package variables. You'd need PadWalker for lexicals.

ikegami Over a year ago

Had wrong stricture. It's no strict qw( refs ); that's needed. Fixed

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