I have a string for items separated by comma. Each item is surrounded by quotes ("), but the items can also contain commas (,). So using split(',') creates problems.
How can I split this text properly in Python?
"coffee", "water, hot"
["coffee", "water, hot"]
You can split on separators that contain more than one character. '"coffee", "water, hot"'.split('", "') gives ['"coffee','water, hot"']. From there you can remove the initial and terminal quote mark.
"coffee" were ", ", you'd split incorrectly. Admittedly that seems unlikely, though.import ast
s = '"coffee", "water, hot"'
result = ast.literal_eval(f'[{s}]')
print(result)
invalid syntax.
literal_eval, but I was displeased by the many previous answers doing imho worse hacks. Anyway, this question says "Each item is surrounded by quotes", so if you want to ask about about a different format, I suggest to ask another question.You can use re.findall
import re
s = '"coffee", "water, hot"'
re.findall('"(.*?)"', s) # ['coffee', 'water, hot']
\", which you'd match.Firstly, I defined a function 'del_quote' to remove unnecessary quotes and spaces. Then I split it taking '",' as a separator. then the result was mapped to remove quotes then converted into list.
def del_quote(s):
return s.replace('"','').strip()
x='"coffee", "water, hot"'
result=list(map(del_quote,x.split('",')))
print(result)
You can almost use csv for this:
import csv
from io import StringIO
sio = StringIO()
sio.write('"coffee", "water, hot"')
sio.seek(0)
reader = csv.reader(sio)
print(next(reader))
# Prints ['coffee', ' "water', ' hot"']
The problem is that there is a space before the opening quote of "water, hot". If you replace '", "' with ",", then csv will work, and you will get ['coffee', 'water, hot'].
How about:
string = '"coffee", "water, hot"'
stringList = string.split("'")
string = stringList[0]
print(string)
