python password generator loop problem print error

Question

I trying to make a password generator using python. Currently, I just want the program to print random characters from the ascii table. I will later introduce numbers and symbols. I used a for loop to print random character from a range that the user inputs. It works however, when I use the end='' to print the characters on the same line a % shows up. I think it is there to show that it printed a no character. I would like the program to not print the % because later I will add other numbers and symbols.

I tried subtracting 1 from the range of number. What resulted was the same string with a % but 1 less than intended. I also tried creating a while loop that would print while the variable was less than the password number. It also printed the %.

Here is the code:

import random
import string
letters=string.ascii_letters
passwordnumber=int(input("How many characters do you want your password to be? "))
for i in range(passwordnumber):
    print(random.choice(letters), end='')

Strange..For me it's not showing % see - onlinegdb.com/9EagkKVW1 — Bhargav
– Bhargav, Commented Nov 22, 2022 at 7:06
Your code works perfectly for me. No %. Don't know where it can come from. No % the rest of the time ? How do you run your script ? From a linux shell ? — 0x0fba
– 0x0fba, Commented Nov 22, 2022 at 7:06
To be sure. Create create a string that contains the generated password and print the last character. First : password = "".join([random.choice(letters) for _ in range(passwordnumber)]). Then : print(password[-1]) — 0x0fba
– 0x0fba, Commented Nov 22, 2022 at 7:10
Veekxt helped me. It was my terminal. I am using vscode and it was a reminder. I am sorry I don't know how to reply. Thank you for all the help. — moomoo
– moomoo, Commented Nov 22, 2022 at 7:16

veekxt · Accepted Answer · 2022-11-22 07:11:55Z

1

The % print by your shell (may be zsh), it means the string not end by "\n". It's just a reminder from the shell. There is nothing wrong with you. You can just add a print() in the end of your code to print a "\n", and % will not show again.

edited Nov 22, 2022 at 7:11

answered Nov 22, 2022 at 7:05

veekxt

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Comments

Nitin Ashutosh · Accepted Answer · 2022-11-22 07:10:21Z

0

Try this

characters = list(string.ascii_letters + string.digits + "!@#$%^&*()")
def generate_random_password():
  ## length of password from the user
  length = 8

  ## shuffling the characters
  random.shuffle(characters)

  ## picking random characters from the list
  password = []
  for i in range(length):
    password.append(random.choice(characters))

  ## shuffling the resultant password
  random.shuffle(password)

  ## converting the list to string
  ## printing the list
  return "".join(password)

answered Nov 22, 2022 at 7:10

Nitin Ashutosh

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Comments

Bhargav · Accepted Answer · 2022-11-22 07:11:42Z

0

Your script works absolutly fine in my side. see this https://onlinegdb.com/9EagkKVW1

If you feel like it's issue with end you can simply concat outputs to string and print at once like so.

import random
import string
letters=string.ascii_letters
pas =''
passwordnumber=int(input("How many characters do you want your password to be? "))
for i in range(passwordnumber):
    pas += random.choice(letters)
   
print(pas)

outputs #

How many characters do you want your password to be? 5
AvfYm

answered Nov 22, 2022 at 7:11

Bhargav

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Comments

lroth · Accepted Answer · 2022-11-22 07:31:17Z

0

we can use the random .sample() method. it requires 2 arguments:

- iterable of elements to use

- number of elements to take

the result does not contain duplicates.

import random
import string
letters=string.ascii_letters
passwordnumber=int(input("How many characters do you want your password to be? "))
pas = ''.join(random.sample(letters, k=passwordnumber))
print(pas)

answered Nov 22, 2022 at 7:31

lroth

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