Is it possible to take user input for a 2D array using pointer names in C?

1. Use meaningful variables names. Who can know if i is the row or column.
2. You need to multiply the row by number of columns.
3. You want reference to the first element of the array not to the one outside the array bounds.
4. Always check the result of scanf.

#define ROWS 3
#define COLS 3

int main(void)
{
    int arr1[ROWS][COLS];
    int *ptr1 = &arr1[0][0];

    for (int row = 0; row < ROWS; row++)
    {
        for (int col = 0; col < COLS; col++)
        {
            if(scanf("%d", ptr1 + row * COLS + col) != 1)
            {
                 /* handle error */
            }
        }
    }
}

You can use a pointer to array. Or in this specific case if you will, a pointer to a row:

#include <stdio.h>

int main(void)
{
    int arr1[3][3];
    int (*ptr1)[3] = arr1;

    for (int i = 0; i < 3; i++)
    {
        for (int j = 0; j < 3; j++)
        {
            scanf("%d", &ptr1[i][j]);
        }
    }
}

Using *(arr + i) etc notation is almost always bad practice, since arr[i] is more readable. There exists no reason why you shouldn't be using the ptr1[i][j] format in this case - unless you like to write unreadable code for the heck of it.

There are already good answer posted. my answer would be side note . In case if we have dynamic 2-D array, below implementation is for that

#include <stdio.h>
#include <stdlib.h>

#define rows 3
#define cols 3

int main ()
{

  //allocate memory equal to [rows * cols]
  int *arr = (int *) malloc (rows * cols * sizeof (int));

  if (arr == NULL)
    {
      printf ("out of memory");
      exit (0);
    }

  // accessing each row and its respective columns.
  // index = row * NumberOfColumns + column
  for (int i = 0; i < rows; i++)
  {
        for (int j = 0; j < cols; j++)
        {
            arr[i * cols + j] = rand () % 10;
        }
  }

  for (int i = 0; i < rows; i++)
  {
        for (int j = 0; j < cols; j++)
        {
            printf ("Row[%d], Column[%d]:%d\n", i, j, arr[i * cols + j]);
        }
  }

  free (arr);

  arr = NULL;

  return 0;
}