Selenium Python: How to set_page_load_timeout, if beyond time return except(not error)

Question

I have this code and how to loop if load timeout it will return except and it run next test case

def search_action(self, xpath, value):

    try:
        self.driver.set_page_load_timeout(1)
        element = self.driver.find_element(By.XPATH, xpath)
        element.send_keys(value)
        element.send_keys(Keys.ENTER)
    except TimeoutException as e:
        print('EXCEPT', e)
        pass

    print('success')


se = class_name()


for domain in config['list_domain']:
    se.get_domain(domain)
    for i in range(1, 100):
        xpath = config[domain]['list_test']['search']
        se.search_action(xpath, i)
        se.get_domain(domain)

return:

selenium.common.exceptions.TimeoutException: Message: timeout: Timed out receiving message from renderer: 0.319

I want loop from 1 to 100 i don't want return error

Prophet · Accepted Answer · 2022-11-29 14:22:30Z

0

I guess your problem is not with set_page_load_timeout.
You need to use WebDriverWait expected_conditions to wait for element to become clickable.

wait.until(EC.element_to_be_clickable((By.XPATH, xpath)))

Since you did not share link and xpath details I can't give more detailed answer here.

answered Nov 29, 2022 at 14:22

Prophet

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2 Comments

Tú Phan Over a year ago

i.e. i want to set timeout 10 if it exceeds the time it returns an exception and it runs the next loop

Tú Phan Over a year ago

important i don't want to stop the loop i want to finish it

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