how to get name of variable in console.log
code1 = 3;
code2 = 1;
code3 = 2;
console.log(Math.min(code1, code2, code3))
result is 1 but want also to print in console.log as : code2 =1
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2You probably want to use an object...epascarello– epascarello2023-04-04 21:45:23 +00:00Commented Apr 4, 2023 at 21:45
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Do you just want this for debugging or something else?epascarello– epascarello2023-04-04 21:45:38 +00:00Commented Apr 4, 2023 at 21:45
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2It's never going to print code2. It's going to print the return value of Math.min().jarmod– jarmod2023-04-04 21:47:45 +00:00Commented Apr 4, 2023 at 21:47
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Hard to understand how you expect your code to do that...Ruan Mendes– Ruan Mendes2023-04-04 21:55:51 +00:00Commented Apr 4, 2023 at 21:55
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2 Answers
const codeValues = {
code1: 3,
code2: 1,
code3: 2,
};
const minValue = Math.min(codeValues.code1, codeValues.code2, codeValues.code3);
const minCodeName = Object.keys(codeValues).find(key => codeValues[key] === minValue);
console.log(`${minCodeName} = ${minValue}`);
5 Comments
Ruan Mendes
Some explanation would be nice
Knowledge Seeker
so, how to insert variables inside codeValues?
Mark Schultheiss
@KnowledgeSeeker That is another question...
Knowledge Seeker
@MarkSchultheiss is there any example?
Mark Schultheiss
Depends on what you mean but that - a question with what you tried and expected output would suffice
You can use it like this
const nums=[3,1,2]
const minIndex= nums.indexOf(Math.min(...nums)),
codeName= `code${minIndex+1}`
console.log(`${codeName} = ${nums[minIndex]}`)
1 Comment
Knowledge Seeker
all your efforts are appreciated :)