Looping multiple arrays simultaneously

Question

Doing a homework assignment and I'm not sure I can wrap my mind around how to go about this problem. I have two arrays with the same amount of values:

$monthsShort = array("Jan", "Feb", ..., "Nov", "Dec");
$monthsLong = array("January", "February", ..., "November", "December");

I need a loop that will traverse both of them and generate output that looks like this:

1 Jan January

2 Feb February

...

12 Dec December

I'm just really not sure where to begin as I can't find a similar problem in my textbook. I did find this: Foreach loop with multiple arrays, but I am not sure how/why it works. Any help is greatly appreciated.

Regardless of the example data you provided. Make sure the arrays are the same length! — Mosty Mostacho
– Mosty Mostacho, Commented Oct 2, 2011 at 23:43

KingCrunch · Accepted Answer · 2011-10-03 00:02:54Z

5

for ($i = 0; $i < 12; $i++) {
  $p = $i+1;
  echo "$p {$monthsShort[$i]} {$monthsLong[$i]}";
}

edited Oct 3, 2011 at 0:02

answered Oct 2, 2011 at 23:37

KingCrunch

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1 Comment

hakre Over a year ago

in case it matters: echo $i+1;

Brendan Long · Accepted Answer · 2011-10-02 23:38:34Z

4

You can get a single index of an array by using this syntax:

$myArray = array("Jan", "Feb", "etc.");
echo $myArray[0]; // prints "Jan"
echo $myArray[1]; // prints "Feb"

The only trick is that you want the indexes to be a variable too, which you can use a for loop for. This will print "JanFebetc.":

for($i = 0; $i < count($myArray); $i++) {
    echo $myArray[$i];
}

Those two together should let you loop through both arrays at the same time.

answered Oct 2, 2011 at 23:38

Brendan Long

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Comments

hakre · Accepted Answer · 2011-10-02 23:40:27Z

3

The example you have picked is for arrays inside arrays, you actually have two arrays you would like to iterate over at once. That's something different.

You can first combine both arrays with array_map^Docs and then iterate over the new array:

$monthsShort = array("Jan", "Feb", '...', "Nov", "Dec");
$monthsLong = array("January", "February", '...', "November", "December");

$map = array_map(NULL, $monthsShort, $monthsLong);

foreach($map as $month => $value)
{
    list($short, $long) = $value;
    printf("%d %s %s\n", $month+1, $short, $long);
}

See the demo. As often in programming, there are more than one solution to a problem, I choose array_map to easily iterate over one array.

answered Oct 2, 2011 at 23:40

hakre

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Comments

macintosh264 · Accepted Answer · 2011-10-02 23:36:01Z

1

$index = 0;
foreach ($monthsShort as $month) {
    echo $index+1 . " " . $month . " " . $monthsLong[$index] . "\n";
    $index++;
}

Easy!

answered Oct 2, 2011 at 23:36

macintosh264

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Comments

user142162 · Accepted Answer · 2011-10-02 23:36:13Z

1

I would do this using a for loop, as you can see below:

for($i = 0; $i < 12; $i++)
{
    printf("%d %s %s<br />\n", $i + 1, $monthsShort[$i], $monthsLong[$i]);
}

answered Oct 2, 2011 at 23:36

user142162

Comments

KingCrunch · Accepted Answer · 2011-10-02 23:37:38Z

0

$output = '';
$count = count($monthsShort);
for ($i = 0; $i < $count; $i++) {
  $output .= $i . ' ' . $monthsShort[$i] . ' ' . $monthsLong[$i] . '<br />';
}
echo $output;

edited Oct 2, 2011 at 23:37

KingCrunch

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answered Oct 2, 2011 at 23:37

Clive

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Comments

Mob · Accepted Answer · 2011-10-02 23:58:17Z

0

Use the count function to count the items in the array

<?php
    $monthsShort = array("Jan", "Feb", "Nov", "Dec");
    $monthsLong = array("January", "February", "November", "December");

    for($i=0;$i<count($monthsLong);$i++){
        echo $i." ".$monthsShort[$i]." ".$monthsLong[$i]."\n";
    }

?>

Outputs

0 Jan January
1 Feb February
2 Nov November
3 Dec December

answered Oct 2, 2011 at 23:58

Mob

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