Selenium Wait for all elements with selector specified

Question

I have something like this

el = WebDriverWait(browser, 10).until(
    EC.presence_of_all_elements_located((By.CSS_SELECTOR, "till-cap"))
)

The problem with the above code is that it does not wait for all the element, it returns 5 instead of 12 elements, sometimes the elements could be more or less, I resolved this by using time.sleep(15) in python, to wait for 15 seconds. But I feel this is not the best way to resolve this. Thank you.

By using time.sleep(15), you get all of the desired elements? Is there a reason you do not want to use this method? If so, please update your question with why — thetaco
– thetaco, Commented Dec 27, 2023 at 15:42
Yes, I do, But I feel there are better ways to do this. Thank you — habibnuhu
– habibnuhu, Commented Dec 27, 2023 at 15:47
if the DOM is still populating, a Stale Element Exception will be thrown when calling a method on one of the elements. You can catch that and re-get the array if caught. I functionize and re-call function if caught... here's a method using time and while loop: stackoverflow.com/questions/66820416/… You can adjust accordingly. — browsermator
– browsermator, Commented Dec 27, 2023 at 18:06

thetaco · Accepted Answer · 2023-12-27 16:08:11Z

1

Although this functionality is not a native function in Selenium, you can implement a lambda function to verify how many elements are present before moving on:

WebDriverWait(browser,10).until(lambda method: len(EC.presence_of_all_elements_located(By.CSS_SELECTOR, "till-cap")) == 12)

Java has Selenium-native functionality for this exact use case, but in Python we must improvise with the lambda method. To avoid a lambda, you could place your time.sleep() after the WebDriverWait function, as the rest of the elements often populate shortly after the first element:

el = WebDriverWait(browser, 10).until(
    EC.presence_of_all_elements_located((By.CSS_SELECTOR, "till-cap"))
)
time.sleep(2)

This could allow you to decrease the time required in time.sleep(), but you will likely have to test a few times to see the minimum time required.

edited Dec 27, 2023 at 16:08

answered Dec 27, 2023 at 15:58

thetaco

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5 Comments

habibnuhu Over a year ago

Using this approach will only check if the elements returned == 12, if elements is more or less, this will fail

thetaco Over a year ago

You can adjust "==12" to be whatever suits you. Do you want it greater than or equal to 12? okay, use ">= 12" . If you're unsure how many elements there will be, then the "sleep()" method will be best.

habibnuhu Over a year ago

Yes, I am not sure of exactly how many elements will be returned

thetaco Over a year ago

Okay, then placing sleep after your WebDriverWait function sounds like the best solution.

thetaco Over a year ago

Of course. Cheers, Habib!

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