how to assign multiple field into a variable?

Question

i would like to convert the data.txt file into the following output using awk 1liner

cat data.txt

personA neta netb netc

personB meta metb metc metd

....

output:

personA has {neta netb netc} items in his bag
personB has {meta metb metc metd} items in his bag

matchew · Accepted Answer · 2011-10-17 04:41:21Z

2

this is a good use for subtr() and index().

awk '{print $1FS"has {"substr($0,index($0,$2))"} itmes in his bag."}' data.txt

output:

personA has {neta netb netc} itmes in his bag.

personB has {meta metb metc metd} itmes in his bag.

answered Oct 17, 2011 at 4:41

matchew

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Vaughn Cato · Accepted Answer · 2011-10-17 03:00:39Z

1

awk '{$1=$1" has";$2="{"$2;print $0"} items in his bag"}' data.txt

answered Oct 17, 2011 at 3:00

Vaughn Cato

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glenn jackman · Accepted Answer · 2011-10-17 13:10:17Z

1

while read line; do
  set -- $line
  person=$1
  shift
  printf "%s has {$s} items in his bag" "$person" "$*"
done < data.txt

answered Oct 17, 2011 at 13:10

glenn jackman

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imm · Accepted Answer · 2011-10-17 02:56:27Z

0

What about:

awk '{ items=""; 
       for(i=2;i<=NF;i++) {items=items" "$i}; 
       gsub(/^[ ]/, "", items);
       print $1" has {"items"} items in his bag" }' data.txt

answered Oct 17, 2011 at 2:56

imm

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