1

I'm looking for template code to sort template arguments by the return value of their static member function static constexpr int getType(), something like:

#include <iostream>
#include <type_traits>

struct A {
    static constexpr int getType() { return 1; }
};

struct B {
    static constexpr int getType() { return 2; }
};

struct C {
    static constexpr int getType() { return 3; }
};

template <typename...T>
struct Sort { /*...*/ };

int main() {
    using Sorted = Sort<C, A, B>::type; // std::tuple<A, B, C> or something like
    std::cout << typeid(Sorted).name() << std::endl;
    return 0;
}

Anyway, I want a typename sequence in ascending order in any form.

2 Answers 2

1

Using Boost.Mp11 you can

#include <boost/mp11.hpp>

using namespace boost::mp11;

template<class LHS, class RHS>
struct Less : std::bool_constant<LHS::getType() < RHS::getType()> {};

template <typename... Ts>
struct Sort {
  using type = mp_sort<mp_list<Ts...>, Less>;
};

which produces a mp_list with the types sorted.

Demo

Sign up to request clarification or add additional context in comments.

Comments

0

OK, I made it -- a compile time quick sort!

#include <iostream>
#include <typeinfo>

template <typename T1, typename T2>
struct compare {
    static constexpr bool less = T1::value < T2::value;
};

template <typename... Seq>
struct Sequence {
};

template <typename S1, typename S2>
struct SequenceExtend;

template <typename... Seq1, typename... Seq2>
struct SequenceExtend<Sequence<Seq1...>, Sequence<Seq2...>> {
    using type = Sequence<Seq1..., Seq2...>;
};

template <typename S, typename T>
struct SequenceAppend;

template <typename... Seq, typename T>
struct SequenceAppend<Sequence<Seq...>, T> {
    using type = Sequence<Seq..., T>;
};

template <typename Pivot, typename Seq>
struct SequencePartition;

template <typename Pivot, typename First>
struct SequencePartition<Pivot, Sequence<First>> {
    using less = std::conditional_t<compare<First, Pivot>::less, Sequence<First>, Sequence<>>;
    using greater = std::conditional_t<!compare<First, Pivot>::less, Sequence<First>, Sequence<>>;
};

template <typename Pivot, typename First, typename...Rest>
struct SequencePartition<Pivot, Sequence<First, Rest...>> {
    using less = std::conditional_t<
        compare<First, Pivot>::less,
        typename SequenceAppend<typename SequencePartition<Pivot, Sequence<Rest...>>::less, First>::type,
        typename SequencePartition<Pivot, Sequence<Rest...>>::less
    >;

    using greater = std::conditional_t <
        !compare<First, Pivot>::less,
        typename SequenceAppend<typename SequencePartition<Pivot, Sequence<Rest...>>::greater, First>::type,
        typename SequencePartition<Pivot, Sequence<Rest...>>::greater
    >;
};

template <typename... Ts>
struct QuickSort {
private:
    template <typename S>
    struct SortPass;

    template <>
    struct SortPass<Sequence<>> {
        using type = Sequence<>;
    };

    template <typename T>
    struct SortPass<Sequence<T>> {
        using type = Sequence<T>;
    };

    template <typename Pivot, typename... Rest>
    struct SortPass<Sequence<Pivot, Rest...>> {
        using less = typename SequencePartition<Pivot, Sequence<Rest...>>::less;
        using greater = typename SequencePartition<Pivot, Sequence<Rest...>>::greater;
        using type = typename SequenceExtend<
            typename SequenceAppend<typename SortPass<less>::type, Pivot>::type,
            typename SortPass<greater>::type
        >::type;
    };

public:
    using type = typename SortPass<Sequence<Ts...>>::type;
};

struct A {
    static constexpr int value = 1;
};

struct B {
    static constexpr int value = 2;
};

struct C {
    static constexpr int value = 3;
};

int main() {
    using sorted1 = QuickSort<A, B, C>::type;
    using sorted2 = QuickSort<A, C, B>::type;
    using sorted3 = QuickSort<B, A, C>::type;
    using sorted4 = QuickSort<B, C, A>::type;
    using sorted5 = QuickSort<C, A, B>::type;
    using sorted6 = QuickSort<C, B, A>::type;

    return 0;
}

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.