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I have the following code in Python 3

def inputWithDefault(text:str, default):
    result = input(f"{" " * int(len(text))}{default}\r{text}")
    return default if not(result is type(default)) else result

Python says this when in the syntax-tree generation stage

  File "main.py", line 2
    result = input(f"{" " * int(len(text))}{default}\r{text}")
                                                             ^
SyntaxError: f-string: expecting '}'

This is difficult to work through as the error is unclear and its reasoning is difficult to parse, I have checked and the {} match up throughout the fstring declaration.

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4
  • Your problem is that f"{" does not contain a closing }. You have two string literals there and the f applies only to the first. I can't really tell what you're trying to do or why you wrote it as two separate string literals, so I can't advise you further on that. Commented Sep 30, 2024 at 16:27
  • 3
    Your f-string has nested double quotes: ". You need python 3.12 or better to parse that. Commented Sep 30, 2024 at 16:33
  • 1
    What's the question? For example, maybe you want to ask why this error is occurring when the braces are in fact balanced. Please edit to clarify and write a more specific title. (On that note, input() is irrelevant to the problem.) For tips, see How to Ask. Commented Sep 30, 2024 at 17:07
  • 2
    BTW, the last line of your code doesn't make any sense. result is type(default) will never be true because result is always a string, never a type. If you want an actual (editable) default value to input(), see Show default value for editing on Python input possible? or (non-editable) How to define default value if empty user input in Python? Commented Sep 30, 2024 at 17:20

2 Answers 2

Reset to default
1

I have moved the spaces at the start into a variable spacing like so removing the errors

def inputWithDefault(text:str, default):
    spacing = " " * int(len(text))
    result = input(f"{spacing}{default}\r{text}")
    return default if not(result is type(default)) else result
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Comments

1

you can use single quotes on the inside

def inputWithDefault(text: str, default):
    result = input(f"{' ' * int(len(text))}{default}\r{text}")
    return default if not isinstance(result, type(default)) else result
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1 Comment

Why did you change the type check? That's irrelevant to the problem. (Also, I don't think this technique even works, but I'm not totally sure what OP intended to do.)

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