Parse string as XML and read all elements [duplicate]

Question

I have a string variable that contains XML:

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<osm attribution="http://www.openstreetmap.org/copyright" copyright="OpenStreetMap and contributors" generator="openstreetmap-cgimap 2.0.1 (3329554 spike-07.openstreetmap.org)" license="http://opendatacommons.org/licenses/odbl/1-0/" version="0.6">
     
        <way changeset="123350178" id="26695601" timestamp="2022-07-08T08:32:16Z" uid="616103" user="Max Tenerelli" version="12" visible="true">
              
            <nd ref="289140256"/>
              
            <nd ref="292764243"/>
              
            <nd ref="291616556"/>
              
            <nd ref="292764242"/>
              
            <nd ref="291616560"/>
              
            <nd ref="291616561"/>
              
            <nd ref="291616562"/>
              
            <tag k="access" v="permissive"/>
              
            <tag k="highway" v="service"/>
              
            <tag k="maxspeed" v="30"/>
              
            <tag k="name" v="Baracconi - Jacotenente"/>
              
            <tag k="oneway" v="no"/>
              
            <tag k="surface" v="paved"/>
             
        </way>
        
    </osm>

I need to read all nd node (ref value) using Python. I built this code but it is not working:

import xml.etree.ElementTree as ET
    root = ET.fromstring(data)
    for eir in root.findall('nodes'):
        print(eir.text)

Your XML does not contain any nodes with tag 'nodes', so findall does not find any. Additionally, the nodes with tag 'nd' do not contain any text, just an attribute. — treuss
– treuss, Commented Nov 13, 2024 at 16:21
This xml does not contain any <nodes> elements. Frankly I do not even understand the question. — John Gordon
– John Gordon, Commented Nov 13, 2024 at 16:27
Find all nd elements with a ref attribute and extract the attribute value: [e.get('ref') for e in root.findall('.//nd[@ref]')]. — ekhumoro
– ekhumoro, Commented Nov 13, 2024 at 18:48

0stone0 · Accepted Answer · 2024-11-13 16:23:38Z

2

You first need to find the way element and search for nd inside
Thus don't search for nodes, but the element name: nd.
There is no .text, to get the attribute use: eir.attrib['ref']

import xml.etree.ElementTree as ET

root = ET.fromstring(input)
way = root.find('way')

for eir in way.findall('nd'):
        print(eir.attrib['ref'])

Output:

Try it online!

answered Nov 13, 2024 at 16:23

0stone0

45.5k6 gold badges53 silver badges82 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Parse string as XML and read all elements [duplicate]

1 Answer 1

Try it online!

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related