None type when parsing xml data in Python

Question

I'd like to be able to parse some info from xml data while uses namespaces. I have been trying to read/follow steps in: https://docs.python.org/3/library/xml.etree.elementtree.html#parsing-xml-with-namespaces

This is a sample of how my xml looks like

When I try going through xml tree using a nested for loop, it looks like my code can read the sub-elements successfully.

def toXML(s):
    xmlRoot= ET.fromstring(s)
    
    for child in xmlRoot:
        print(child.tag)
        for subchild in child:
            print(subchild.tag)
            for subchild in subchild:
                print(subchild.tag)

Output:

{http://www.w3.org/2003/05/soap-envelope}Body
{http://www.onvif.org/ver10/search/wsdl}GetRecordingSummaryResponse
{http://www.onvif.org/ver10/search/wsdl}Summary

Process finished with exit code 0

However, when I try to do this the nice way

    for child in xmlRoot.find('{http://www.onvif.org/ver10/search/wsdl}Summary'):
        NumberRecordings=child.find('{http://www.onvif.org/ver10/schema}NumberRecordings')
        print(NumberRecordings.text)

I get this error:

for child in xmlRoot.find('{http://www.onvif.org/ver10/search/wsdl}Summary'):
                 ~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
TypeError: 'NoneType' object is not iterable

Any idea why my child is None ?

Use .findall(), not .find(). find() returns a single element or None, you can't iterate over either of them. — Barmar
– Barmar, Commented Apr 2 at 21:40
It doesn't say that child is None. It says that xmlRoot.find() returns None, and you can't loop over that. — Barmar
– Barmar, Commented Apr 2 at 21:40
If you do this xmlRoot.find('.//{http://www.onvif.org/ver10/search/wsdl}Summary') this should work. — Hermann12
– Hermann12, Commented Apr 3 at 10:52

Hermann12 · Accepted Answer · 2025-04-03 10:32:49Z

0

You can find the text values with find(".//prefix:tagname", namespace). No need for interation.

from lxml import etree

xmlFile = "your_xml_file.xml"
root = etree.parse(xmlFile).getroot()
ns = root.nsmap

dataFrom = root.find(".//tt:Data-From", ns).text
print(dataFrom)

dataUntil = root.find(".//tt:DataUntil", ns).text
print(dataUntil)

numberRecords = root.find(".//tt:NumberRecordings", ns).text
print(numberRecords)

Output:

2025-03-19T15:22:10z
2025-03-19T18:30:52Z
1

Or as an shorter alternative search for <tse:Summary> with find() and iterate over the childs:

for elem in root.find(".//tse:Summary", ns):
    print(elem.text)

edited Apr 3 at 10:32

answered Apr 3 at 10:18

Hermann12

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