Django - skip first row of array

Question

I have a fairly simple question, but I can't seem to find a simple solution to it. I'd like to iterate through an array in my Django template but skip the first value.

Let's say I have an array like this that I pass to my template through a view:

array = ['1', '2', '3', '4', '5']

In my template I do :

{% for a in array %} {{ a }} {% endfor %}

How can I do to only print '2' '3' '4' '5', without the first value ?

Jeremy Lewis · Accepted Answer · 2011-11-03 11:05:47Z

30

{% for a in array|slice:"1:" %}{{ a }}{% endfor %}

See https://docs.djangoproject.com/en/1.3/ref/templates/builtins/#slice for more information.

answered Nov 3, 2011 at 11:05

Jeremy Lewis

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2 Comments

Johanna Over a year ago

Works perfectly thanks. I'll look into this slice function, I didn't know about it

pmalbu Over a year ago

Having trouble with this when the array is a Queryset. I think @Some programmer dude's answer works more universally.

Some programmer dude · Accepted Answer · 2011-11-03 11:11:42Z

9

{% for a in array %}
  {% if not forloop.first %}
    {{ a }}
  {% endif %}
{% endfor %}

There is of course forloop.last for the last iteration as well.

They are all listed in the Django reference.

answered Nov 3, 2011 at 11:11

Some programmer dude

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Comments

Timmy O'Mahony · Accepted Answer · 2011-11-03 11:06:47Z

2

{% for a in array %}
{% if forloop.counter != 1 %}
    {{ a }}
{% endif %}
{% endfor %}

answered Nov 3, 2011 at 11:06

Timmy O'Mahony

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1 Comment

Timmy O'Mahony Over a year ago

@Jeremy Lewis's solution is probably cleaner unless you want to do something with the first value

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