I have a string:
$string = '<a href="/news/blablalba">some text</a>';
I need to add target="_blank" attribute inside tag above and http://mysite.kz before /news/blablabla.
preg_replace("/<a href=\"\/(.*)\">(.*)<\/a>/iU", "<a target=\"_blank\" href=\"\/(.*)\">(.*)\">(.*)<\/a>", $string);
code above won't works. Help please!
UPDATED
Solved this task:
$match1 = preg_replace("/<a href=\"\/(.*)\">(.*)<\/a>/i", "<a target=\"_blank\" href=\"http://nashmir.kz/$1\">$2</a>", $string);
preg_replace('/^<a\s+(href=")(\/news\/)/i', '<a target="_blank" $1http://mysite.kz$2')
Rule of thumb: you only need to match what is necessary. Except in very rare cases, you never need to match the whole input.
<a\s+, you try and match h, then r, then..., then a quote and then another quote. Similarly, at the end of the regex, you try and match two slashes after the s of news.
(). In regex language, this is called a grouping. It has two properties: it captures so that you can use backreferences (which $1 and $2 are), and makes the contained regex atomic wrt quantifiers such as *, +, etc.