regular expression to add characters before and after numbers

Question

I have a list of numbers between square brackets, and I need to add words before and after the exact numbers (i.e. keep the same numbers). I use notepad++ to replace, but if you have a solution with other program please advise.

Example:

text [121] othertext
moretext [16] othertextmore
andtext [5940] othertextplus

outcome:

text xxxxxxxxx [121] xxxxxxxxx othertext
moretext xxxxxxxxx [16] xxxxxxxxx othertextmore
andtext xxxxxxxxx [5940] xxxxxxxxx othertextplus

The numbers are of course \d+ but I want to tell it to keep the same numbers when looking.

While the regex sill stay the same, the code will change: WHich Language? — Eugen Rieck
– Eugen Rieck, Commented Dec 24, 2011 at 10:48

manojlds · Accepted Answer · 2011-12-24 10:49:20Z

25

Find What: (\[\d+])

Replace With: xxxxxxxxx \1 xxxxxxxxx

enter image description here

answered Dec 24, 2011 at 10:49

manojlds

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4 Comments

manojlds Over a year ago

@Mike - You can accept as answer by clicking on the tick on the left.

Tim Pietzcker Over a year ago

No need for parentheses if you're going to use the entire match anyway - replace with xxxxxx \0 xxxxxx.

Tim Pietzcker Over a year ago

Really? Interesting but not surprising given Notepad++'s lackluster regex support.

JinSnow Over a year ago

don't forget to put your search statement into parenthesis

Mukul Aggarwal · Accepted Answer · 2017-07-05 10:05:00Z

5

Regular expression:

Find regex = \[\d+\]
Replace regex = xxxxxxxxx$&xxxxxxxxx

Refer: regexr

answered Jul 5, 2017 at 10:05

Mukul Aggarwal

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Comments

Eugen Rieck · Accepted Answer · 2011-12-24 10:53:09Z

2

C#:

line=Regex.Replace(line,@"([^\[])(\[\d+\])(.*)","$1xxxxxxxxx $2 xxxxxxxxx$3");

Other languages analogous

answered Dec 24, 2011 at 10:53

Eugen Rieck

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