Spring mvc: Dynamic 404 page

Question

<error-page>
    <error-code>404</error-code>
    <location>/404.html</location>
</error-page>

This is my current configuration for 404 errors.

What I want: When a person types www.host.com/word . I want the string "word" as input for my search url (which is www.host.com/search.do?keyword).

Does anyone know how to do this?

Paul · Accepted Answer · 2012-01-27 17:09:11Z

3

Map / to your DispatcherServlet (see section 16.2 of the Spring reference documentation) and set up a URI template as shown in section 16.3.2.1. For example, you could set up a request mapping like so:

@RequestMapping(value="/{keyword}", method=RequestMethod.GET)
public ModelAndView doSearch(@PathVariable("keyword") String keyword)
{
  // forward to your search page
}

edited Jan 27, 2012 at 17:09

answered Jan 27, 2012 at 15:16

Paul

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6 Comments

Hidde B Over a year ago

<servlet-mapping> <servlet-name>frontend</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <servlet> <servlet-name>frontend</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet>

Paul Over a year ago

Yes, I've amended my answer to link to the relevant section in the Spring documentation. If my answer solved your problem please accept it by clicking the checkmark next to it.

Hidde B Over a year ago

Is it true that everything behind host.com/ is now mapped to the dispatcher? Because my homepage doesnt show up right anymore (css, javascript).

Paul Over a year ago

Yes. You could map the servlet to search/ instead so search/{keyword} be the url instead.

Hidde B Over a year ago

Can you give me an example of this please? What to i need to put in the web.xml?

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