Is it possible to get such info by some API or function, rather than parsing the /proc/cpuinfo?
9 Answers
From man 5 proc:
/proc/cpuinfo This is a collection of CPU and system architecture dependent items, for each supported architecture a different list. Two common entries are processor which gives CPU number and bogomips; a system constant that is calculated during kernel initialization. SMP machines have information for each CPU.
Here is sample code that reads and prints the info to console, stolen from forums - It really is just a specialized cat command.
#define _GNU_SOURCE
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv)
{
FILE *cpuinfo = fopen("/proc/cpuinfo", "rb");
char *arg = 0;
size_t size = 0;
while(getdelim(&arg, &size, 0, cpuinfo) != -1)
{
puts(arg);
}
free(arg);
fclose(cpuinfo);
return 0;
}
Please note that you need to parse and compare the physical id, core id and cpu cores to get an accurate result, if you really care about the number of CPUs vs. CPU cores. Also please note that if there is a htt in flags, you are running a hyper-threading CPU, which means that your mileage may vary.
Please also note that if you run your kernel in a virtual machine, you only see the CPU cores dedicated to the VM guest.
3 Comments
You can use this for mostly all kind of linux distro
For C code
num_cpus = sysconf( _SC_NPROCESSORS_ONLN );
(In QNX systems , you can use num_cpus = sysinfo_numcpu())
For shell scripting, you can use cat /proc/cpuinfo
or use lscpu or nproc commands in linux
libcpuid provides a simple API which will directly return all the CPU features, including number of cores. To get the number of cores at runtime, you could do something like this:
#include <stdio.h>
#include <libcpuid.h>
int main(void)
{
if (!cpuid_present()) {
printf("Sorry, your CPU doesn't support CPUID!\n");
return -1;
}
struct cpu_raw_data_t raw;
struct cpu_id_t data;
if (cpuid_get_raw_data(&raw) < 0) {
printf("Sorry, cannot get the CPUID raw data.\n");
printf("Error: %s\n", cpuid_error());
return -2;
}
if (cpu_identify(&raw, &data) < 0) {
printf("Sorrry, CPU identification failed.\n");
printf("Error: %s\n", cpuid_error());
return -3;
}
printf("Processor has %d physical cores\n", data.num_cores);
return 0;
}
3 Comments
configure && make && sudo make install and make failed, might be something really simple :)Read /proc/cpuinfo
Sample Output
processor : 0
model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz
cache size : 6144 KB
physical id : 0
siblings : 4
core id : 0
cpu cores : 4
processor : 1
model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz
cache size : 6144 KB
physical id : 0
siblings : 4
core id : 1
cpu cores : 4
processor : 2
model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz
cache size : 6144 KB
physical id : 0
siblings : 4
core id : 2
cpu cores : 4
processor : 3
model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz
cache size : 6144 KB
physical id : 0
siblings : 4
core id : 3
cpu cores : 4
show_cpuinfo is the function which actually implements the /proc/cpuinfo functionality
Comments
Add following line in your source code..
system("cat /proc/cpuinfo | grep processor | wc -l");
This will print number of cpus in your system. And if you want to use this output of this system call in your program than use popen system call.
2 Comments
Parse the file /proc/cpuinfo. This'll give you lot of details about the CPU. Extract the relevant fields into your C/C++ file.
1 Comment
Depending on your flavor of Linux you will get different results from /proc/cpuid.
This works for me on CentOS for getting total number of cores.
cat /proc/cpuinfo | grep -w cores | sed -e 's/\t//g' | awk '{print $3}' | xargs | sed -e 's/\ /+/g' | bc
The same doesn't work in Ubuntu. For Ubuntu you can use the following command.
nproc
3 Comments
cat. The following will work just fine: grep -m1 "cores" /proc/cpuinfo | tr -d '[a-z]:[:space:]'cat /proc/cpuinfo | grep -w cores | sed -e 's/\t//g' | awk '{print $3}' | xargs | sed -e 's/\ /+/g' | bc worked at least on Ubuntu-22.04.