XML parsing with Jquery

Question

<resultGroups> 
    <subGroups>
        <results> </results>
        <name></name>
    </subGroups>
    <subGroups>
        <results> </results>
        <name></name>
    </subGroups>    
    <name>myname</name>
</resultGroups>
<resultGroups> 
    <subGroups>
        <results> </results>
        <results> </results>
        <name></name>
    </subGroups>
    <subGroups>
        <results> </results>
        <results> </results>
        <name></name>
    </subGroups>    
    <name>othername</name>
</resultGroups>

how can i select the name tag of first resultGroup only using jquery???

@Jasim: Why do you keep posting the same question over and over again? stackoverflow.com/questions/980413/xml-parsing-in-jquery - stackoverflow.com/questions/985500/xml-parsing-jquery? What about reading the documentation to the part of jQuery that is always used in the answers to these questions? — Tomalak
– Tomalak, Commented Jun 12, 2009 at 11:14
Have you considered marking the answers as answered if it fits your need? or provide a comment if you need any further assistance? — Shadi Almosri
– Shadi Almosri, Commented Jun 12, 2009 at 14:59

Shadi Almosri · Accepted Answer · 2009-06-12 11:20:30Z

4

$.ajax({
    url: "result.xml",
    dataType: "xml",
    success: function(data){
        // Parsing happens here

    }
 });

To parse the document we have two main functions available "each" and "find". The function "each" will loop over all the tags with a specific name, the function "find" will search for a certain tag.

$(data).find("resultGroup").each(function() {
    alert("found a resultGroup");
});


$(data).find("resultGroup").each(function() {
        alert($(this).find("subgroups").text());
});


$(data).find("subgroups").each(function() {
        alert($(this).attr("result"));
});

edited Jun 12, 2009 at 11:20

answered Jun 12, 2009 at 11:14

Shadi Almosri

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1 Comment

Shadi Almosri Over a year ago

Just to make a note i haven't tested this code, just wrote it out, so you might need to tweak it a little to get the right results :) but it should give you a good basis to understand the answer,

Alan Plum · Accepted Answer · 2009-06-12 11:14:40Z

0

$('resultGroup subGroups name')[0]

If you want to be more specific, you could split the selection and fetch the first array index for each:

$('name', $('subGroups', $('resultGroup')[0])[0])

... I think.

answered Jun 12, 2009 at 11:14

Alan Plum

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