How to ignore if array(0) is null php

Question

When i am print the value the array is like this: Array ( [0] => )

if i print count($testArray) it is showing 1

But if the array value is comes like this i don't want to insert it into the database. Please suggest how can i do this.

Update:

var_dump result: array(1) { [0]=> string(0) "" }

empty($testArray[0]) should return true, then you can skip, otherwise (if $testArray[0] has any kind of value other than null-values) it returns false. — TRD
– TRD, Commented Mar 27, 2012 at 14:12

vicky · Accepted Answer · 2012-03-27 14:11:07Z

8

Use this

 array_filter($testArray);

answered Mar 27, 2012 at 14:11

vicky

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Comments

Travesty3 · Accepted Answer · 2012-03-27 14:10:21Z

0

if (!empty($testArray[0]))
    // do something

OR

foreach ($testArray as $value)
{
    if (!empty($value))
    {
        // do something
    }
}

answered Mar 27, 2012 at 14:10

Travesty3

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Comments

Baba · Accepted Answer · 2012-03-27 14:12:53Z

0

This would help you filter the array

    $array1 = array("a"=>1, "b"=>2, "c"=>3, "d"=>4, "e"=>5,"f"=>"","i"=>0);
    function filter($var)
    {
        return !empty($var);
    }
    var_dump(array_filter($array1, "filter"));

Output

    array
      'a' => int 1
      'b' => int 2
      'c' => int 3
      'd' => int 4
      'e' => int 5

answered Mar 27, 2012 at 14:12

Baba

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Comments

Patroklo · Accepted Answer · 2012-03-27 14:13:36Z

0

You can try

if(!isset($testArray[0]))
{
    //here the zero key has null value
}

or

if($testArray[0] == NULL)
{
    //here the zero key has null value
}

But try first:

var_dump($testArray);

And let us know what it's shown.

answered Mar 27, 2012 at 14:13

Patroklo

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2 Comments

vvr Over a year ago

var_dump result: array(1) { [0]=> string(0) "" }

Patroklo Over a year ago

Then the array value is not null, it's an empty string. Try: if($testArray[0] == '')

perror · Accepted Answer · 2016-01-26 18:07:17Z

0

I was trying to ignore an empty value but some of the codes didn't work. So I tried this and works, maybe this code will help someone out there.

if (empty($YourValue)){ continue; } else { echo $YourValue; }

The code continue skips your empty value.

It helps me creating a navbar inside <li> ... </li> code for some reason.

edited Jan 26, 2016 at 18:07

perror

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answered Jan 26, 2016 at 17:35

DagicCross

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