PHP Search values in array - Return true if all are numbers, false if not

Question

Ok, Stupid question here... just trying to do a search in an array to be sure all of the values are numeric, if not, I need to return false. What's the quickest way to do this. This array could be HUGE. By the way, it's not a multi-dimensional array, and doesn't have any sub-arrays within it. It's just a one level array... example:

array(1, 5, 6, 2, 44, 92, 50, string);

This should return false, cause string is one of the values in the array and is not a number. I mean, is there a faster way to do this than using foreach on the array and using intval on every value??

Thanks guys :)

MD Sayem Ahmed · Accepted Answer · 2012-04-01 06:45:15Z

3

You can use is_numeric function -

$count = count($your_array);

for($index=0; $index<$count; $index++)
{
    if( !is_numeric($your_array[index]) )
        return false;
}

answered Apr 1, 2012 at 6:45

MD Sayem Ahmed

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3 Comments

tttony Over a year ago

is_numeric is checking the array

MD Sayem Ahmed Over a year ago

@tttony: Sorry, forgot to index it. Thanks for pointing it out!

SoLoGHoST Over a year ago

Thanks, guess I'm going with this one since it has the most up votes. No offense guys.

Aditya M P · Accepted Answer · 2012-04-01 06:59:59Z

3

  if(in_array(false, array_map("is_numeric", array(1, 2, 3, 4, 5, "string"))))
    return false;

I have not researched the performance, sorry. But these are inbuilt functions which are allegedly faster than anything custom one can write...

answered Apr 1, 2012 at 6:59

Aditya M P

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1 Comment

Yamiko Over a year ago

haven't seen that function before. Nice Info this should be the best solution.

Yamiko · Accepted Answer · 2012-04-01 07:04:02Z

1

foreach($array as $value)
{
    if(!is_numeric($value))
    {
       return false;
    }
}

edited Apr 1, 2012 at 7:04

answered Apr 1, 2012 at 6:53

Yamiko

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2 Comments

Eugeny89 Over a year ago

and why have you put the braces on line 3?

Yamiko Over a year ago

it was a shorthand if statement which is (condition ? true : false) but it doesn't work in that situation. Been a while since I used one.

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