When I open CMD (on windows 10) and enter python it initializes python 3.6.0
C:\>python
Python 3.6.0 (v3.6.0:41df79263a11, Dec 23 2016, 08:06:12) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>>
Now I recently also installed 2.7.6 the interpreter. How can I call both version of Python from CMD?
desired outcome
C:\>python
Python 3.6.0 (v3.6.0:41df79263a11, Dec 23 2016, 08:06:12) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>>
>>> ^Z
C:\>python2.6
Python 2.7.6 (default, Nov 10 2013, 19:24:24) [MSC v.1500 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>>
PATHenvironment variable. Or just use the py.exe launcher, e.g.py -2orpy -2.7.