Foreach Array error (PHP)

Question

I want to create dynamic menu with looping an array be 1 object menu. But error occured. Our code is below it:

$menus = [{"id" => 1, "label" => "content", "parent_id" => 0},{"id" => 2, "label" => "inbox", "id" => 3, "parent_id" => 0}, {"id" => 4, "label" => "item", "parent_id" => 0}];
$sub_menus = [{"id" => 5, "label" => "banner", "parent_id" => 1},{"id" => 6, "label" => "ads", "parent_id" => 1}];

foreach($menus as $row => $value){
    $nav[$row] = $value;
    foreach($sub_menus as $r => $v) {
        if($v['parent_id'] == $value['id']){
            $nav[$row]['sub_menu'][$r] = $v;
        }
     }
 }

I get error notif, "Indirect modification of overloaded element of App\Menu has no effect"

Please Help me :)

$menus,$sub_menus both are not php array, instead of {} write [] — Shams Reza
– Shams Reza, Commented Apr 12, 2018 at 11:08
Provide a sample of your expected output , So that we can understand better. — Shams Reza
– Shams Reza, Commented Apr 12, 2018 at 11:10
issue in the first line. You have 2 "id"s. {"id" => 2, "label" => "inbox", "id" => 3, "parent_id" => 0}, — Basavaraj Bhusani
– Basavaraj Bhusani, Commented Apr 12, 2018 at 11:16

Mike Foxtech · Accepted Answer · 2018-04-12 11:09:54Z

3

The code is working. You have a lot of bugs in your arrays.

Fixed:

$menus = [
            [
                "id" => 1,
                "label" => "content",
                "parent_id" => 0
            ],
            [
                "id" => 2,
                "label" => "inbox",
                "parent_id" => 0
            ],
            [
                "id" => 4,
                "label" => "item",
                "parent_id" => 0
            ]
        ];

        $sub_menus = [
            [
                "id" => 5,
                "label" => "banner",
                "parent_id" => 1
            ],
            [
                "id" => 6,
                "label" => "ads",
                "parent_id" => 1
            ]
        ];

        foreach($menus as $row => $value){
            $nav[$row] = $value;
            foreach($sub_menus as $r => $v) {
                if($v['parent_id'] == $value['id']){
                    $nav[$row]['sub_menu'][$r] = $v;
                }
            }
        }

answered Apr 12, 2018 at 11:09

Mike Foxtech

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1 Comment

bajaklaut201180 Over a year ago

yes it work, I have failed because in my laravel framework I pull a data from database not use referense toArray. Thanks Mike :)

overals · Accepted Answer · 2018-04-12 11:29:33Z

0

You have a broken array, something like an incorrect conversion of json to an array;

You can test(execute) it here (working example)

answered Apr 12, 2018 at 11:29

overals

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1 Comment

bajaklaut201180 Over a year ago

yes it work, I have failed because in my laravel framework I pull a data from database not use referense toArray. Thanks Overals. Big thanks for your suggest about your link wtools.io :D its Awesome !!! I use it now

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