Duplication while concatenating regex in javascript [duplicate]

Question

I have a string, in which I am doing replace operation with the help of regex.It is done, in order to replace the particular character in the string, if that exists and to retain others.

var text = "abcdef";

var text = ((text.replace(/a/g, '1')) + (text.replace(/b/g, '2')) + (text.replace(/c/g, '3')));

Expected Output: 123def

But I am getting the output like this: 1bcdefa2cdefab3def

revo · Accepted Answer · 2018-09-25 10:52:14Z

1

Your code does not work because you are concatenating the replace instead of chaining them.

var text = "abcdef";

var text = text.replace(/a/g, '1').replace(/b/g, '2').replace(/c/g, '3');
console.log(text);

However the recommended way is to use a single replace for it.

edited Sep 25, 2018 at 10:52

revo

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answered Sep 25, 2018 at 10:49

Ankit Agarwal

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3 Comments

aadhira Over a year ago

Thanks. It worked!

Ankit Agarwal Over a year ago

@srikha you could do var text = text.replace(/abc/g, '123')

Ankit Agarwal Over a year ago

@srikha but if abc can occur at random places separately then use separate replace()

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