in my application user can be register and my application can save user information with sqlite, each registered user can be verify his mobile number with sms and user can active his account on application by userActive item on database
now, i have some list of items witch that created by class:
final List<DashboardItems> dashboardItems = [
DashboardItems(menuItem: MenuItems.dashboard, title: Strings.drawerItemHome, icon: 'assets/icons/home.png', forActiveUser: false),
DashboardItems(menuItem: MenuItems.healthProfile, title: Strings.drawerItemProfile, icon: 'assets/icons/cannabis.png', forActiveUser: true),
];
in application and there are some items for registered user and who active account by sms, in DashboardItems class this field is forActiveUser
for example suppose i have simple Container, who can i colorize white that for active users?
with below code i should be have one white container as MenuItems.dashboard and one gray container as MenuItems.healthProfile.
but i have two white container
decoration: BoxDecoration(
color:
user != null && user.userActive == 1 ? Colors.white :
user == null || (user != null && user.userActive == 0) || !item.forActiveUser ? Colors.white :
Colors.grey,
borderRadius: BorderRadius.all(Radius.circular(5.0)),
boxShadow: [
BoxShadow(
blurRadius: 0.5,
color: Colors.black,
offset: Offset(0.0, 0.0),
)
]),
UPDATED:
container should be white when:
`user!=null` and `user.userActive`==1 <-- all containers should be white
otherwise:
`user` is `null` && `user!=null and user.userActive==0` <-- containers should be gray when `forActiveUser` is true