Find an object by its key, if two keys of two different objects within an array of object are identical in JavaScript [duplicate]

Question

Here is an array of objects:

var array = [{ first: "Romeo", last: "Capulet" }, { first: "Mercutio", last: null }, { first: "Tybalt", last: "Capulet" }]

Here is an object:

var obj = {last: "Capulet}

Trying to find an object by its key, if two keys of two objects are the same! If this object obj is contained within above array of object by one of its properties and value, it suppose to return entire object of above mentioned array of object. For example in this case it should return an array of two objects because two objects contain property "last" with its value "Capulet"!

[{ first: "Romeo", last: "Capulet" }, { first: "Tybalt", last: "Capulet" }]

This is my code:

function objectFindByKey(array, obj){
    var array1 = [];
    for(var i = 0; i<array.length;i++){
        array1.push(Object.entries(array[i]));
        var a2 = JSON.stringify(array1);
        var a3 = JSON.stringify(obj);
        if(a2.includes(a3)){
            return array1[i];
        };
    };
};

To be able to compare two objects I used JSON.stringify() method because in that case if I stringify an array of objects. Unfortunately it returns "undefined" at the end!

do you want a new object? have you tried something?

Nina Scholz
– Nina Scholz

2021-02-20 12:03:01 +00:00
Commented Feb 20, 2021 at 12:03 — Nina Scholz
– Nina Scholz, Commented Feb 20, 2021 at 12:03
Yes, I would like new object!

Ivan Vrzogic
– Ivan Vrzogic

2021-02-20 12:03:59 +00:00
Commented Feb 20, 2021 at 12:03 — Ivan Vrzogic
– Ivan Vrzogic, Commented Feb 20, 2021 at 12:03

Mamun · Accepted Answer · 2021-02-20 12:07:04Z

1

You can loop through the object keys and delete the property if condition matches:

var obj = {a: 1, b: 2, c: 3, d: 4, e: 5, f: 6, g: 7, h: 8, i: 9, j: 10};
Object.keys(obj).forEach(function(k){
  if(obj[k]<5){
    delete obj[k];
  }
});

console.log(obj);

answered Feb 20, 2021 at 12:07

Mamun

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1 Comment

T.J. Crowder Over a year ago

OP clarified later they want a new object.

Nina Scholz · Accepted Answer · 2021-02-20 12:07:28Z

0

You could filter the entries.

const
    object = { a: 1, b: 2, c: 3, d: 4, e: 5, f: 6, g: 7, h: 8, i: 9, j: 10 };
    result = Object.fromEntries(Object
        .entries(object)
        .filter(([_, v])=> v >= 5)
    );

console.log(result);

answered Feb 20, 2021 at 12:07

Nina Scholz

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