Cannot call constexpr template member function in consteval constructor

// gcc: ok
// clang: compile error
struct arg
{
    consteval arg(const int i)  // consteval
        : i_(i)
    {
        chk<int>(i);  // error!!
    }

    template <typename T>
    constexpr void chk(const T i)  // template member
    {}

    int i_;
};

void f(arg i)
{}

int main()
{
    f(10);
    return 0;
}

demo: https://godbolt.org/z/cjjGz7xP9

I'm working with GCC and Clang in C++23.

When calling a constexpr template member function in a consteval constructor, Clang rejects the program. It compains:

<source>:39:7: error: call to consteval function 'arg::arg' is not a constant expression
   39 |     f(10);
      |       ^
<source>:23:9: note: undefined function 'chk<int>' cannot be used in a constant expression
   23 |         chk<int>(i);
      |         ^

I tested some modifications (see the demo). The code at the top is the one for #define case 2.

• case 1: If the arg::arg constructor is changed to constexpr, of course the errors are gone.
• case 3: If arg::chk() is changed to a non-template member, it compiles.
• case 4: If chk() is changed to a regular template function (not a member), it compiles.

If Clang's rejection is right, I wonder why the error occurs only when arg::chk() is a template and a member function, and why Clang says undefined function 'chk<int>'.