I am passing date as variable in function. I want to convert that date in different format. Example
DT=2015-12-08
Want to convert DT to 08-dec-2015 in Unix.
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Using what programming language?Majenko– Majenko2015-12-13 18:07:44 +00:00Commented Dec 13, 2015 at 18:07
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2 Answers
Assuming GNU date (i.e. non-embedded Linux):
$ LC_TIME=C date --date=2015-12-08 +%d-%b-%Y
08-Dec-2015
If you're on a non-embedded Linux, or more generally a system with GNU date, you can use it to typeset an arbitrary date.
LC_ALL=C date -d "$DT" +%d-%b-%Y | tr A-Z a-z
If you don't have GNU date (or even if you do), you can do this in pure shell.
case $DT in
*-01-*|*-1-*) month=jan;;
*-02-*|*-2-*) month=feb;;
*-03-*|*-3-*) month=mar;;
*-04-*|*-4-*) month=apr;;
*-05-*|*-5-*) month=may;;
*-06-*|*-6-*) month=jun;;
*-07-*|*-7-*) month=jul;;
*-08-*|*-8-*) month=aug;;
*-09-*|*-9-*) month=sep;;
*-10-*) month=oct;;
*-11-*) month=nov;;
*-12-*) month=dec;;
esac
echo "${DT##*-}-$month-${DT%%-*}"
answered Dec 13, 2015 at 23:49
Gilles 'SO- stop being evil'
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