1

I have this string for example : 

asddsa "ll" sadd " fsgsg"
"sdafaf" "lkkx" "fsgfgsg"

I want to substitute all characters inside " " with a character x. Expected output in this case should be: 

asddsa "x" sadd " x"
    "x" "x" "x"

I tried something like this : sed 's/".*"/"x"/g' but the output is logically

asddsa "x" "x"

How could I fix my regexp to get the right output?

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1 Answer 1

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2

A dot . means any character. But you don't want it to match a double quote; you want it to match anything but a double quote. So specify that with a character class:

sed 's/"[^"]*"/"x"/g'
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