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C: create a pointer to two-dimensional array
When an array is defined, as
int k[100];
it can be cast to int*:
int* pk = k;
It there a pointer variable a multidimensional array can be cast to?
int m[10][10];
??? pm = m;
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3 Answers
int m[10][20];
int (*pm)[20] = m; // [10] disappears, but [20] remains
int t[10][20][30];
int (*pt)[20][30] = m; // [10] disappears, but [20][30] remain
This is not a "cast" though. Cast is an explicit type conversion. In the above examples the conversion is implicit.
Not also that the pointer type remains dependent on all array dimensions except the very first one. It is not possible to have a completely "dimensionless" pointer type that would work in this context, i.e. an int ** pointer will not work with a built-in 2D array. Neither will an int *** pointer with a built-in 3D array.
answered Dec 4, 2012 at 7:35
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Comments
Yes ofcourse , You can have pointer to multidimentional array.
int m[10][10];
int (*pm)[10] = m;
Comments
How about this:
int k[100];
int* pk = k;
int m[10][10];
int **ptr = (int **) malloc(10 * sizeof(int*));
for(int i=0;i<10;i++)
{
ptr[i] = m[i];
}
