Getting an image if it exists with variable file name

Question

Pretty much explains itself. If I just just get the image to load with this:

<img src="/dm cricket/admin/img/tables/<?php htmlout($name);?>_2.jpg">

it works, but if I decide to change the code to this:

<?php if(file_exists('/dm cricket/admin/img/tables/'.$name.'_2.jpg')){
    ?>
<img src="/dm cricket/admin/img/tables/<?php htmlout($name);?>_2.jpg"><?php }
else {
    echo 'No competition held';}?>

it doesn't work, it only echoes 'No competition held'. Can anyone explain why?

A hint for you: Your document root is problably not your filesystem root. — Carsten
– Carsten, Commented Jan 10, 2013 at 12:18

Quentin · Accepted Answer · 2013-01-10 12:13:08Z

1

A root relative URI from the URI of the page as fetched over HTTP is not going to be the same thing as a file path on the file system of the web server.

Assuming a simple configuration of the server, you would have to prefix the file path with the path to the server's web root directory.

answered Jan 10, 2013 at 12:13

Quentin

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1 Comment

cameronjonesweb Over a year ago

Ah ok, I get it. Added the following to the front of the directory and it worked $_SERVER['DOCUMENT_ROOT'] .

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