PHP fatal Error require_once

Question

Hello Guys can anyone explain why is this happening to my program

when i use this Folder structure

enter image description here

and the code inside database.php is

<?php require_once("../db_config.php");?>

I get an error Fatal error: require_once(): Failed opening required '../db_config.php' (include_path='.;F:\xampp\php\PEAR') in F:\xampp\htdocs\project\database\db_mysql\database.php on line 3'

but when i move the db_config.php

enter image description here

Everything works fine. I don't get it. Can anyone explain.I prefer to use the first Folder structure because i will add a new folder db_mssql for mssql database.

I believe you are on windows and windows prefers backslash to forwardslash — Satya
– Satya, Commented Feb 6, 2013 at 2:56
@Satya thanks but i use all forwardslash in my links and it still working. — Snippet
– Snippet, Commented Feb 6, 2013 at 3:00

MDS · Accepted Answer · 2013-02-06 03:01:02Z

3

<?php require_once("../db_config.php");?>

Try

<?php require_once("../../db_config.php");?>

Better yet use

require_once($_SERVER['DOCUMENT_ROOT'] . 'directory/directory/file');

answered Feb 6, 2013 at 3:01

MDS

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2 Comments

Snippet Over a year ago

require_once($_SERVER['DOCUMENT_ROOT'] . '/directory/directory/file'); Thanks this one works. But this code <?php require_once(" ../db_config.php");?> doesn't work? can you explain why?

MDS Over a year ago

The ../ is the equivilent of a directory in the directory structure. Each one tells the code to look up to its parent directory. db_config.php is located 2 directories(including the one that it is located in) higher than database.php. It's like folderception!

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