Shell script declaring date variable

Question

Below is the script i wrote.

#!/usr/bin/expect -f
#!/bin/bash

# connect via scp

Y_DATE=`$(date --date yesterday "+%Y-%m-%d")`

spawn scp /apps/Train/jboss-soa-p.5.0.0/jboss-as/server/default/log/server.log.$Y_DATE  "xxxx@Tdev:/apps/software/copiedLogFiles/"

expect "password:"
send "buildadmin\$123\r"
expect "*\r"
expect "\r"

and i am getting below error while executing script.

can't read "(date --date yesterday "+%Y-%m-%d")": no such variable
    while executing
"Y_DATE=`$(date --date yesterday "+%Y-%m-%d")`"
    (file "./copySITtoUAT_CDS.sh" line 6)

I am not able to figure out what's the error in Y_DATE declaration? Am i missing something here.

fedorqui · Accepted Answer · 2013-02-06 14:09:17Z

2

Maybe it is this: You can use either

Y_DATE=$(date --date yesterday "+%Y-%m-%d")

or

Y_DATE=`date --date yesterday "+%Y-%m-%d"`

But not both.

answered Feb 6, 2013 at 14:09

fedorqui

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1 Comment

Jite Over a year ago

Preferably $() (simplifies when it gets to nesting).

Madhu CM · Accepted Answer · 2013-02-12 14:05:34Z

0

I modified my script as below and it worked.

#!/bin/sh

LOG_DIR=/apps/jboss/jboss-soa-p.5.0.0/jboss-as/server/mssql_prod1/log
SRS_HOST=XPSIT
USER_ID=xambas
PSWD=abackc
Y_DIR=`find $LOG_DIR -name "server.log*" \( -mtime -1 -and -not -daystart -mtime 0 \)`
cd $LOG_DIR
Y_FILE=`find . -name "server.log*" \( -mtime -1 -and -not -daystart -mtime 0 \)`
cd -
export Y_FILE SRS_HOST USER_ID PSWD Y_DIR

expect -c '
        spawn scp "$env(Y_DIR)" "$env(USER_ID)@$env(SRS_HOST):/apps/soft/Prod_LOG/Prod_A/$env(Y_FILE)"
        expect "password:"
        send "$env(PSWD)\r"
        expect "*\r"
        expect "\r"

answered Feb 12, 2013 at 14:05

Madhu CM

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Comments

ti3um · Accepted Answer · 2016-02-05 11:09:18Z

0

The following code works :

Y_DATE=`date --date yesterday +%Y-%m-%d`

answered Feb 5, 2016 at 11:09

ti3um

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