Store date variable in bash script

Question

I want to store date values into a variable for future use. Please correct the sample script:

#!/bin/bash
Now_hourly = $(date +%d-%b-%H_%M)    
Now_daily = $(date +%d-%b-daily)    
echo $(Now_hourly)    
echo $(Now_daily)

The output should be : 12-Feb-17_50 and 12-Feb-daily
But When I run the script, I am getting below error :
Now_hourly: command not found
Now_daily: command not found

It's a FAQ. You can't have spaces on either side of = while assigning a variable. — devnull
– devnull, Commented Feb 12, 2014 at 7:59
This question appears to be off-topic because the OP expects the reader to correct the sample script. — devnull
– devnull, Commented Feb 12, 2014 at 8:01
@Gopu you can get the correct answer by testing everything that reach to your mind..no problem..It is solved :) — MLSC
– MLSC, Commented Feb 12, 2014 at 8:38
Besides: use curly braces in the echo lines, otherwise Now_hourly will be tried to execute. — urzeit
– urzeit, Commented Feb 12, 2014 at 8:41

MLSC · Accepted Answer · 2014-02-12 08:39:01Z

52

you can change the script like:

#!/bin/bash
Now_hourly=$(date +%d-%b-%H_%M)    
Now_daily=$(date +%d-%b-daily)    
echo "$Now_hourly"
echo "$Now_daily"

I think the problem is spaces around =

output:

12-Feb-12_03
12-Feb-daily

edited Feb 12, 2014 at 8:39

answered Feb 12, 2014 at 8:32

MLSC

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1 Comment

imnd_neel Over a year ago

Also, as a generic answer, if your date format may contain spaces, you should keep the format in double quotes, like so --> Now_hourly=$(date +"%d-%b-%H_%M")

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